Integrand size = 28, antiderivative size = 242 \[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}-\frac {2 a (22 b c-9 a d) \sqrt {c+d x^2}}{77 c^2 e^3 (e x)^{7/2}}-\frac {2 \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \sqrt {c+d x^2}}{231 c^3 e^5 (e x)^{3/2}}-\frac {d^{3/4} \left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \left (\sqrt {c}+\sqrt {d} x\right ) \sqrt {\frac {c+d x^2}{\left (\sqrt {c}+\sqrt {d} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),\frac {1}{2}\right )}{231 c^{13/4} e^{13/2} \sqrt {c+d x^2}} \]
-2/11*a^2*(d*x^2+c)^(1/2)/c/e/(e*x)^(11/2)-2/77*a*(-9*a*d+22*b*c)*(d*x^2+c )^(1/2)/c^2/e^3/(e*x)^(7/2)-2/231*(77*b^2*c^2-5*a*d*(-9*a*d+22*b*c))*(d*x^ 2+c)^(1/2)/c^3/e^5/(e*x)^(3/2)-1/231*d^(3/4)*(77*b^2*c^2-5*a*d*(-9*a*d+22* b*c))*(cos(2*arctan(d^(1/4)*(e*x)^(1/2)/c^(1/4)/e^(1/2)))^2)^(1/2)/cos(2*a rctan(d^(1/4)*(e*x)^(1/2)/c^(1/4)/e^(1/2)))*EllipticF(sin(2*arctan(d^(1/4) *(e*x)^(1/2)/c^(1/4)/e^(1/2))),1/2*2^(1/2))*(c^(1/2)+x*d^(1/2))*((d*x^2+c) /(c^(1/2)+x*d^(1/2))^2)^(1/2)/c^(13/4)/e^(13/2)/(d*x^2+c)^(1/2)
Result contains complex when optimal does not.
Time = 11.18 (sec) , antiderivative size = 196, normalized size of antiderivative = 0.81 \[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=\frac {x^{13/2} \left (-\frac {2 \left (c+d x^2\right ) \left (77 b^2 c^2 x^4+22 a b c x^2 \left (3 c-5 d x^2\right )+3 a^2 \left (7 c^2-9 c d x^2+15 d^2 x^4\right )\right )}{c^3 x^{11/2}}-\frac {2 i d \left (77 b^2 c^2-110 a b c d+45 a^2 d^2\right ) \sqrt {1+\frac {c}{d x^2}} x \operatorname {EllipticF}\left (i \text {arcsinh}\left (\frac {\sqrt {\frac {i \sqrt {c}}{\sqrt {d}}}}{\sqrt {x}}\right ),-1\right )}{c^3 \sqrt {\frac {i \sqrt {c}}{\sqrt {d}}}}\right )}{231 (e x)^{13/2} \sqrt {c+d x^2}} \]
(x^(13/2)*((-2*(c + d*x^2)*(77*b^2*c^2*x^4 + 22*a*b*c*x^2*(3*c - 5*d*x^2) + 3*a^2*(7*c^2 - 9*c*d*x^2 + 15*d^2*x^4)))/(c^3*x^(11/2)) - ((2*I)*d*(77*b ^2*c^2 - 110*a*b*c*d + 45*a^2*d^2)*Sqrt[1 + c/(d*x^2)]*x*EllipticF[I*ArcSi nh[Sqrt[(I*Sqrt[c])/Sqrt[d]]/Sqrt[x]], -1])/(c^3*Sqrt[(I*Sqrt[c])/Sqrt[d]] )))/(231*(e*x)^(13/2)*Sqrt[c + d*x^2])
Time = 0.35 (sec) , antiderivative size = 255, normalized size of antiderivative = 1.05, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {365, 27, 359, 264, 266, 761}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx\) |
| \(\Big \downarrow \) 365 |
| \(\displaystyle \frac {2 \int \frac {11 b^2 c x^2+a (22 b c-9 a d)}{2 (e x)^{9/2} \sqrt {d x^2+c}}dx}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
| \(\Big \downarrow \) 27 |
| \(\displaystyle \frac {\int \frac {11 b^2 c x^2+a (22 b c-9 a d)}{(e x)^{9/2} \sqrt {d x^2+c}}dx}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
| \(\Big \downarrow \) 359 |
| \(\displaystyle \frac {\frac {\left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \int \frac {1}{(e x)^{5/2} \sqrt {d x^2+c}}dx}{7 c e^2}-\frac {2 a \sqrt {c+d x^2} (22 b c-9 a d)}{7 c e (e x)^{7/2}}}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
| \(\Big \downarrow \) 264 |
| \(\displaystyle \frac {\frac {\left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \left (-\frac {d \int \frac {1}{\sqrt {e x} \sqrt {d x^2+c}}dx}{3 c e^2}-\frac {2 \sqrt {c+d x^2}}{3 c e (e x)^{3/2}}\right )}{7 c e^2}-\frac {2 a \sqrt {c+d x^2} (22 b c-9 a d)}{7 c e (e x)^{7/2}}}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
| \(\Big \downarrow \) 266 |
| \(\displaystyle \frac {\frac {\left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \left (-\frac {2 d \int \frac {1}{\sqrt {d x^2+c}}d\sqrt {e x}}{3 c e^3}-\frac {2 \sqrt {c+d x^2}}{3 c e (e x)^{3/2}}\right )}{7 c e^2}-\frac {2 a \sqrt {c+d x^2} (22 b c-9 a d)}{7 c e (e x)^{7/2}}}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
| \(\Big \downarrow \) 761 |
| \(\displaystyle \frac {\frac {\left (77 b^2 c^2-5 a d (22 b c-9 a d)\right ) \left (-\frac {d^{3/4} \left (\sqrt {c} e+\sqrt {d} e x\right ) \sqrt {\frac {c e^2+d e^2 x^2}{\left (\sqrt {c} e+\sqrt {d} e x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),\frac {1}{2}\right )}{3 c^{5/4} e^{7/2} \sqrt {c+d x^2}}-\frac {2 \sqrt {c+d x^2}}{3 c e (e x)^{3/2}}\right )}{7 c e^2}-\frac {2 a \sqrt {c+d x^2} (22 b c-9 a d)}{7 c e (e x)^{7/2}}}{11 c e^2}-\frac {2 a^2 \sqrt {c+d x^2}}{11 c e (e x)^{11/2}}\) |
(-2*a^2*Sqrt[c + d*x^2])/(11*c*e*(e*x)^(11/2)) + ((-2*a*(22*b*c - 9*a*d)*S qrt[c + d*x^2])/(7*c*e*(e*x)^(7/2)) + ((77*b^2*c^2 - 5*a*d*(22*b*c - 9*a*d ))*((-2*Sqrt[c + d*x^2])/(3*c*e*(e*x)^(3/2)) - (d^(3/4)*(Sqrt[c]*e + Sqrt[ d]*e*x)*Sqrt[(c*e^2 + d*e^2*x^2)/(Sqrt[c]*e + Sqrt[d]*e*x)^2]*EllipticF[2* ArcTan[(d^(1/4)*Sqrt[e*x])/(c^(1/4)*Sqrt[e])], 1/2])/(3*c^(5/4)*e^(7/2)*Sq rt[c + d*x^2])))/(7*c*e^2))/(11*c*e^2)
3.9.48.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c ^2*(m + 1))) Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p }, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2), x _Symbol] :> Simp[c*(e*x)^(m + 1)*((a + b*x^2)^(p + 1)/(a*e*(m + 1))), x] + Simp[(a*d*(m + 1) - b*c*(m + 2*p + 3))/(a*e^2*(m + 1)) Int[(e*x)^(m + 2)* (a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] && !ILtQ[p, -1]
Int[((e_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^2, x _Symbol] :> Simp[c^2*(e*x)^(m + 1)*((a + b*x^2)^(p + 1)/(a*e*(m + 1))), x] - Simp[1/(a*e^2*(m + 1)) Int[(e*x)^(m + 2)*(a + b*x^2)^p*Simp[2*b*c^2*(p + 1) + c*(b*c - 2*a*d)*(m + 1) - a*d^2*(m + 1)*x^2, x], x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1]
Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[( 1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))* EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]
Time = 3.08 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.03
| method | result | size |
| risch | \(-\frac {2 \sqrt {d \,x^{2}+c}\, \left (45 a^{2} d^{2} x^{4}-110 x^{4} a b c d +77 b^{2} c^{2} x^{4}-27 a^{2} c d \,x^{2}+66 a b \,c^{2} x^{2}+21 a^{2} c^{2}\right )}{231 c^{3} x^{5} e^{6} \sqrt {e x}}-\frac {\left (45 a^{2} d^{2}-110 a b c d +77 b^{2} c^{2}\right ) \sqrt {-c d}\, \sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {e x \left (d \,x^{2}+c \right )}}{231 c^{3} \sqrt {d e \,x^{3}+c e x}\, e^{6} \sqrt {e x}\, \sqrt {d \,x^{2}+c}}\) | \(249\) |
| elliptic | \(\frac {\sqrt {e x \left (d \,x^{2}+c \right )}\, \left (-\frac {2 a^{2} \sqrt {d e \,x^{3}+c e x}}{11 e^{7} c \,x^{6}}+\frac {2 a \left (9 a d -22 b c \right ) \sqrt {d e \,x^{3}+c e x}}{77 e^{7} c^{2} x^{4}}-\frac {2 \left (45 a^{2} d^{2}-110 a b c d +77 b^{2} c^{2}\right ) \sqrt {d e \,x^{3}+c e x}}{231 e^{7} c^{3} x^{2}}-\frac {\left (45 a^{2} d^{2}-110 a b c d +77 b^{2} c^{2}\right ) \sqrt {-c d}\, \sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right )}{231 c^{3} e^{6} \sqrt {d e \,x^{3}+c e x}}\right )}{\sqrt {e x}\, \sqrt {d \,x^{2}+c}}\) | \(273\) |
| default | \(-\frac {45 \sqrt {2}\, \sqrt {-c d}\, \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, F\left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) a^{2} d^{2} x^{5}-110 \sqrt {2}\, \sqrt {-c d}\, \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, F\left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) a b c d \,x^{5}+77 \sqrt {2}\, \sqrt {-c d}\, \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, F\left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) b^{2} c^{2} x^{5}+90 a^{2} d^{3} x^{6}-220 x^{6} d^{2} a b c +154 b^{2} c^{2} d \,x^{6}+36 a^{2} c \,d^{2} x^{4}-88 a b \,c^{2} d \,x^{4}+154 b^{2} c^{3} x^{4}-12 a^{2} c^{2} d \,x^{2}+132 a b \,c^{3} x^{2}+42 a^{2} c^{3}}{231 \sqrt {d \,x^{2}+c}\, x^{5} c^{3} e^{6} \sqrt {e x}}\) | \(411\) |
-2/231*(d*x^2+c)^(1/2)*(45*a^2*d^2*x^4-110*a*b*c*d*x^4+77*b^2*c^2*x^4-27*a ^2*c*d*x^2+66*a*b*c^2*x^2+21*a^2*c^2)/c^3/x^5/e^6/(e*x)^(1/2)-1/231*(45*a^ 2*d^2-110*a*b*c*d+77*b^2*c^2)/c^3*(-c*d)^(1/2)*((x+(-c*d)^(1/2)/d)/(-c*d)^ (1/2)*d)^(1/2)*(-2*(x-(-c*d)^(1/2)/d)/(-c*d)^(1/2)*d)^(1/2)*(-x/(-c*d)^(1/ 2)*d)^(1/2)/(d*e*x^3+c*e*x)^(1/2)*EllipticF(((x+(-c*d)^(1/2)/d)/(-c*d)^(1/ 2)*d)^(1/2),1/2*2^(1/2))/e^6*(e*x*(d*x^2+c))^(1/2)/(e*x)^(1/2)/(d*x^2+c)^( 1/2)
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.09 (sec) , antiderivative size = 124, normalized size of antiderivative = 0.51 \[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=-\frac {2 \, {\left ({\left (77 \, b^{2} c^{2} - 110 \, a b c d + 45 \, a^{2} d^{2}\right )} \sqrt {d e} x^{6} {\rm weierstrassPInverse}\left (-\frac {4 \, c}{d}, 0, x\right ) + {\left ({\left (77 \, b^{2} c^{2} - 110 \, a b c d + 45 \, a^{2} d^{2}\right )} x^{4} + 21 \, a^{2} c^{2} + 3 \, {\left (22 \, a b c^{2} - 9 \, a^{2} c d\right )} x^{2}\right )} \sqrt {d x^{2} + c} \sqrt {e x}\right )}}{231 \, c^{3} e^{7} x^{6}} \]
-2/231*((77*b^2*c^2 - 110*a*b*c*d + 45*a^2*d^2)*sqrt(d*e)*x^6*weierstrassP Inverse(-4*c/d, 0, x) + ((77*b^2*c^2 - 110*a*b*c*d + 45*a^2*d^2)*x^4 + 21* a^2*c^2 + 3*(22*a*b*c^2 - 9*a^2*c*d)*x^2)*sqrt(d*x^2 + c)*sqrt(e*x))/(c^3* e^7*x^6)
Timed out. \[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=\text {Timed out} \]
\[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{2}}{\sqrt {d x^{2} + c} \left (e x\right )^{\frac {13}{2}}} \,d x } \]
\[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{2}}{\sqrt {d x^{2} + c} \left (e x\right )^{\frac {13}{2}}} \,d x } \]
Timed out. \[ \int \frac {\left (a+b x^2\right )^2}{(e x)^{13/2} \sqrt {c+d x^2}} \, dx=\int \frac {{\left (b\,x^2+a\right )}^2}{{\left (e\,x\right )}^{13/2}\,\sqrt {d\,x^2+c}} \,d x \]